JEE Advanced levelSingle correct optionDifficulty 3 of 3o1207
Acetic formic anhydride, HCO−O−CO−CHX3, reacts with 1 equiv of methylamine at low temperature. The main product is
Amethyl acetate
BN-methylformamide
Cmethyl formate
DN-methylacetamide
Answer: B
The amine attacks the more electrophilic and less hindered formyl carbon (H instead of the electron-releasing, bulkier CHX3). The acetate group is the leaving group, giving N-methylformamide and acetic acid.