Answer: B
The lactone is a cyclic ester. The first CHX3MgBr opens the ring (alkoxide leaves) to give a methyl ketone bearing a terminal CHX2OX−. The ketone adds a second mole, giving a tertiary alkoxide. After work-up: HOCHX2CHX2CHX2−C(CHX3)X2OH, 2-methylpentane-2,5-diol.