Numerical answer type, tolerance 0.5.
Answer: 7
The compound shown is butylamine, C4H11N. The amine isomers are 4 primary (butyl, sec-butyl, isobutyl, tert-butyl), 3 secondary (diethyl, methylpropyl, methylisopropyl) and 1 tertiary (dimethylethyl). Only primary amines give carbylamine, so x = 4; only secondary amines give N-nitrosamines, so y = 3. Hence x + y = 7.