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JEE Advanced levelSingle correct optionDifficulty 3 of 3nc214

Complete reductive cleavage of the N=N bond of 4-hydroxyazobenzene (with $Na X_{2} S X_{2} O X_{4}$ or $Sn / HCl$ ) gives

Aaniline and 4-nitrophenol
Btwo molecules of aniline
Chydrazobenzene only
Daniline and 4-aminophenol

Answer: D

Reduction splits the N=N bond into two N-H bonds on each side:

C X_{6} H X_{5} - N = N - C X_{6} H X_{4} - OH

gives

C X_{6} H X_{5} NH X_{2}

and

H X_{2} N - C X_{6} H X_{4} - OH

(para). Hydrazobenzene would result from partial reduction without cleavage.

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