Answer: C
Sn/HCl gives aniline; acetylation and monobromination give 4-bromoacetanilide (para to the acetamido group); hydrolysis gives 4-bromoaniline. Diazotisation and the Sandmeyer cyanation then replace NX2X+ by CN, giving 4-bromobenzonitrile. The nitrile is not hydrolysed under these conditions.