Which sequence converts aniline into 1,3,5-tribromobenzene?

The strongly activating amino group directs three bromines to the 2,4,6 positions with Br2 water, giving 2,4,6-tribromoaniline. Diazotisation followed by $\mathrm{H}{}_3\mathrm{PO}{}_2$ removes the amino group as N2, leaving bromines at 1,3,5. The other routes give a bromobenzene mixture, 1,2,4,6-tetrabromobenzene or 2,4,6-tribromophenol.