Answer: C
HBFX4 gives the insoluble benzenediazonium tetrafluoroborate, CX6HX5NX2X+BFX4X−. On heating (Balz-Schiemann reaction) it decomposes to CX6HX5F, NX2 and BFX3; the fluorine comes from BFX4X−, and no chloride is involved in this step.