$SO X_{3}$ ( $80 g/mol$ ) dissociates as $2 SO X_{3} 2 SO X_{2} + O X_{2}$ . The equilibrium mixture has a density $34.0$ times that of hydrogen under the same conditions ( $H X_{2} = 2$ g/mol). Find the percent dissociation of $SO X_{3}$ , to two decimals.

Numerical answer type, answer in %, tolerance 0.05.

Answer: 35.29 %

Observed average molar mass = 34.0 x 2 = 68. Start with 1 mol

SO X_{3}

, fraction

α

dissociated: moles = 1 -

α

α

α

/2 = 1 +

α

/2. 80/(1 +

α

/2) = 68, so 1 +

α

/2 = 1.17647 and

α

= 0.3529 = 35.29%.

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