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JEE Main levelNumerical answerDifficulty 2 of 3mc101

dissociates as and is dissociated at equilibrium. Taking , , find the vapour density of the equilibrium mixture, to two decimals.

Numerical answer type, tolerance 0.02.

Answer: 74.46

= 31 + 177.5 = 208.5 g/mol. For 1 mol initially, moles at equilibrium = 1 + 0.4 = 1.4, mass unchanged. Average molar mass = 208.5/1.4 = 148.93; vapour density = 148.93/2 = 74.46.
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