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JEE Main levelNumerical answerDifficulty 2 of 3mc065

of and of react as far as possible in (, ). Find the mass in grams of the reactant left over, to one decimal place.

Numerical answer type, answer in g, tolerance 0.05.

Answer: 4 g

= 0.5 mol, = 0.375 mol. requires only 0.25 mol , so is limiting and is consumed fully. left = 0.375 - 0.25 = 0.125 mol = 4.0 g.
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