JEE Main levelNumerical answerDifficulty 2 of 3mc065
32g of SOX2 and 12g of OX2 react as far as possible in 2SOX2+OX22SOX3 (S=32, O=16). Find the mass in grams of the reactant left over, to one decimal place.
Numerical answer type, answer in g, tolerance 0.05.
Answer: 4 g
SOX2 = 0.5 mol, OX2 = 0.375 mol. SOX2 requires only 0.25 mol OX2, so SOX2 is limiting and is consumed fully. OX2 left = 0.375 - 0.25 = 0.125 mol = 4.0 g.