Fe2O3 + 3CO -> 2Fe + 3CO2. When 32 g of Fe2O3 is heated with 8.4 g of CO, the mass of iron obtained is (Fe = 56, C = 12, O = 16):

JEE Main levelSingle correct optionDifficulty 2 of 3mc044

$Fe X_{2} O X_{3} + 3 CO 2 Fe + 3 CO X_{2}$ . When $32 g$ of $Fe X_{2} O X_{3}$ is heated with $8.4 g$ of CO, the mass of iron obtained is (Fe = 56, C = 12, O = 16):

n (Fe X_{2} O X_{3}) = 32/160 = 0.20

;

n (CO) = 8.4/28 = 0.30

. CO is limiting because

3

mol CO give

2

mol Fe.

n (Fe) = 0.30 \times 2/3 = 0.20

, mass

= 0.20 \times 56 = 11.2 g