A sample of $2.40 kg$ of iron ore contains $64.0%$ $Fe X_{2} O X_{3}$ by mass. Reduction in a blast furnace recovers $90.0%$ of the iron present. Taking Fe = 56 and O = 16, calculate the mass of iron obtained in grams (nearest integer).

Numerical answer type, answer in g, tolerance 0.5.

Answer: 968 g

Mass of

Fe X_{2} O X_{3}

2400 \times 0.640 = 1536 g

. Each

160 g

Fe X_{2} O X_{3}

contains

112 g

Fe, so Fe present is

1536 \times \frac{112}{160} = 1075.2 g

. At

90.0%

recovery the mass obtained is

1075.2 \times 0.900 = 967.68 g

, i.e. about

968 g