JEE Advanced levelSingle correct optionDifficulty 3 of 3mt109
Six moles of PbS are roasted so that exactly half is converted to PbSOX4 (PbS+2OX2PbSOX4) and the rest is left unchanged. Air is then cut off and the mixture heated: PbS+PbSOX42Pb+2SOX2. The volume of OX2 (STP) used in the first stage and the mass of lead finally obtained (Pb = 207) are
A67.2L and 1242g
B268.8L and 1242g
C134.4L and 1242g
D134.4L and 621g
Answer: C
Half of 6 mol is 3 mol PbS, converted using 3×2=6 mol OX2=134.4 L. The remaining 3 mol PbS react with 3 mol PbSOX4 to give 3×2=6 mol Pb. Mass of Pb =6×207=1242 g.