JEE Advanced levelSingle correct optionDifficulty 3 of 3mt055
In the Mond process 1.50kg of crude nickel containing 94.0% Ni is treated with CO at about 330K: Ni+4CONi(CO)X4, and the impurities do not react. With Ni=59, C=12, O=16, and 22.4L/mol at STP, the volume of CO at STP consumed and the mass of Ni(CO)X4 formed are
A2141 L and 4.09 kg
B535 L and 4.09 kg
C3417 L and 4.09 kg
D2141 L and 1.41 kg
Answer: A
Moles of Ni =1410/59=23.898. Each Ni takes 4 CO, so CO =95.59 mol and V=95.59×22.4=2141L. The carbonyl has molar mass 59+4×28=171, so mass =23.898×171=4.09kg. The carbonyl is later decomposed near 450 K to give pure nickel.