Answer: D
The compound is butan-1-ol. Acyclic C4H10O isomers: four alcohols (butan-1-ol, butan-2-ol, 2-methylpropan-1-ol, 2-methylpropan-2-ol) and three ethers (1-methoxypropane, 2-methoxypropane and ethoxyethane). Total 4 + 3 = 7 (enumerated by computer).