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JEE Advanced levelSingle correct optionDifficulty 3 of 3nm270

The compound shown has the molecular formula . Counting the compound shown itself, how many acyclic structural isomers (alcohols and ethers) have this formula? Ignore stereoisomers.

  1. A4
  2. B5
  3. C6
  4. D7

Answer: D

The compound is butan-1-ol. Acyclic C4H10O isomers: four alcohols (butan-1-ol, butan-2-ol, 2-methylpropan-1-ol, 2-methylpropan-2-ol) and three ethers (1-methoxypropane, 2-methoxypropane and ethoxyethane). Total 4 + 3 = 7 (enumerated by computer).
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