Answer: A, B
The compound is 3-ethyl-2-methylpent-1-ene. The chain CH2=C(CH3)-CH(C2H5)-CH2CH3 is pent-1-ene with methyl at C2 and ethyl at C3; ethyl precedes methyl alphabetically. The terminal =CH2 carbon carries two identical hydrogens, so there is no geometrical isomerism.