How many carboxylic acids (structural isomers) have the molecular formula $C X_{5} H X_{10} O X_{2}$ ?

Answer: C

Acid = R-COOH with R = C4H9: four butyl groups (n-butyl, sec-butyl, isobutyl, tert-butyl) give pentanoic acid, 2-methylbutanoic acid, 3-methylbutanoic acid and 2,2-dimethylpropanoic acid. Total 4.

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How many carboxylic acids (structural isomers) have the molecular formula CX5​HX10​OX2​?

Answer: C

More questions on Counting structural isomers

How many carboxylic acids (structural isomers) have the molecular formula $C X_{5} H X_{10} O X_{2}$ ?