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JEE Advanced levelSingle correct optionDifficulty 3 of 3nm103

The IUPAC name of is:

  1. A5-hydroxypent-2-en-4-one
  2. B4-oxopent-2-en-1-ol
  3. C1-hydroxypent-2-en-4-one
  4. D5-hydroxypent-3-en-2-one

Answer: D

Ketone outranks alcohol, so -one is the suffix and gets the lowest locant: numbering from the CH3 end puts C=O at C-2, while the other end would give C-4. The C=C is then C-3=C-4 and the OH is a prefix on C-5. The name is 5-hydroxypent-3-en-2-one.
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