Answer: B
CH2=CH-CH2-CH2-C#CH gives {1,5} either way, so the tie goes to the double bond: hex-1-en-5-yne is correct. CH3-C#C-CH2-CH=CH2 numbered from the CH2= end has the set {1,4}, lower than {2,5}, so it is hex-1-en-4-yne. CH3-CH=CH-C#C-CH3 gives {2,4} both ways, so the double bond gets 2: hex-2-en-4-yne, not hex-4-en-2-yne. CH2=CH-C#C-CH2-CH3 is hex-1-en-3-yne, so only the first statement is correct.