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JEE Main levelSingle correct optionDifficulty 2 of 3nm014

The open-chain hydrocarbons that contain exactly one C=C and one C $\equiv$ C bond form a homologous series. What is the general formula of this series?

A $C X_{n} H X_{2 n - 6}$
B $C X_{n} H X_{2 n}$
C $C X_{n} H X_{2 n - 4}$
D $C X_{n} H X_{2 n - 2}$

Answer: C

The compound has DU = 1 + 2 = 3 and no ring. For a hydrocarbon, H = 2C + 2 - 2(DU) = 2n + 2 - 6 = 2n - 4. For example, n = 7 gives H = 10.

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