MolSynapse
question bank
All chapters
NEET
JEE
Practice
MolSynapse
/
Question bank
/
Ionic Equilibrium I
/
Common ion effect and precipitation
JEE Main level
Single correct option
Difficulty 2 of 3
ie180
K
s
p
of
PbSO
X
4
is
1.6
×
1
0
−
8
. Its solubility in
0.04
M
Na
X
2
SO
X
4
solution (in
mol
L
−
1
) is approximately
A
1.3
×
1
0
−
4
M
B
2.0
×
1
0
−
7
M
C
1.0
×
1
0
−
5
M
D
4.0
×
1
0
−
7
M
Answer: D
[
SO
X
4
X
2
−
]
≈
0.04
M
(dissolved
PbSO
X
4
is negligible), so
s
=
[
Pb
X
2
+
]
=
K
s
p
/0.04
=
4.0
×
1
0
−
7
M
.
Practice Ionic Equilibrium I
More on Common ion effect and precipitation
Previous question
Next question
More questions on Common ion effect and precipitation
Using K_sp(AgCl) = 1.8 x 10^-10, the solubility of AgCl in 0.1 M NaCl solution (in mol L^-1) is approximately
NEET level
Addition of sodium acetate to a solution of acetic acid
NEET level
Assuming ideal behaviour, in which of the following will AgCl be least soluble?
NEET level
50 mL of 2.0 x 10^-3 M Pb(NO3)2 is mixed with 50 mL of 4.0 x 10^-3 M KI. Given K_sp(PbI2) = 8.0 x 10^-9, the correct conclusion is
JEE Main level
Solid NaCl is added gradually (no volume change) to 0.002 M AgNO3. Given K_sp(AgCl) = 1.8 x 10^-10, precipitation just begins when [Cl^-] (i...
JEE Main level
K_sp of PbF2 is 3.6 x 10^-8. Its solubility in 0.1 M Pb(NO3)2 solution (in mol L^-1), neglecting s compared with 0.1, is
JEE Main level