JEE Advanced levelSingle correct optionDifficulty 3 of 3ie093
The pH of 1.0×10−8MHCl at 298 K is nearest to
A6.98
B8
C7.00
D6
Answer: A
The ionisation of water cannot be neglected. Let [HX+]=10−8+y and [OHX−]=y, so y(10−8+y)=10−14, giving y=9.512e−08. [HX+]=1.051e−07M and pH=6.98, still acidic, below 7.