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NEET levelSingle correct optionDifficulty 1 of 3ie056

The pH of a $0.01 M$ solution of $HCl$ at 298 K is

A $1$
B $2$
C $12$
D $0.01$

Answer: B

HCl

is a strong acid, so

[H X^{+}] = 0.01 M = 1 0^{- 2} M

. Hence

pH = - lo g 1 0^{- 2} = 2

.

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