$25.0 mL$ of a strong monoprotic acid of pH $1.30$ is diluted with water to $500 mL$ . Find the pH of the diluted solution to two decimals ( $1 0^{- 1.30} = 0.0501$ ; $lo g 20 = 1.301$ ).

Numerical answer type, tolerance 0.01.

Answer: 2.6

Dilution factor

= 500/25 = 20

, so

pH

rises by

lo g 20 = 1.301

pH = 1.30 + 1.301 = 2.601 \approx 2.60