JEE Advanced levelOne or more correct optionsDifficulty 3 of 3ia220
A solution is 0.10M in HA (Ka=2.0×10−4) and 0.10M in HB (Ka=5.0×10−6). Using [HX+]=KACA+KBCB, select the correct statement(s).
A[BX−]≈1.1×10−4M
B[AX−]≈4.4×10−3M
C[AX−]=[BX−] because both acids are monobasic
DThe pH is about 2.34
Answer: A, B, D
[HX+]=2.0×10−5+5.0×10−7=4.53×10−3M, pH 2.34. [AX−]=KACA/[HX+]=4.42×10−3 and [BX−]=KBCB/[HX+]=1.10×10−4M. They differ by the ratio of the KaC products (≈40), so the last statement is false.