100 mL of 0.20 M Na2CO3 is mixed with 150 mL of 0.10 M HCl. Given pK_a2(H2CO3) = 10.33 and log 3 = 0.477, the pH is

JEE Advanced levelSingle correct optionDifficulty 3 of 3ia216

$100 mL$ of $0.20 M$ $Na X_{2} CO X_{3}$ is mixed with $150 mL$ of $0.10 M$ $HCl$ . Given $p K_{a 2} (H X_{2} CO X_{3}) = 10.33$ and $lo g 3 = 0.477$ , the pH is

CO X_{3} X^{2 -}

20 mmol

;

H X^{+}

15 mmol

, giving

HCO X_{3} X^{-} = 15

and

CO X_{3} X^{2 -} = 5 mmol

pH = 10.33 + lo g (5/15) = 10.33 - 0.477 = 9.85

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