JEE Main levelNumerical answerDifficulty 2 of 3ia179
For HX3POX4, pKa2=7.21 and pKa3=12.35. Treating HPOX4X2− as an amphiprotic species with pH=21(pKa2+pKa3), find the pH of an aqueous NaX2HPOX4 solution (two decimals).
Numerical answer type, tolerance 0.01.
Answer: 9.78
HPOX4X2− is the intermediate between HX2POX4X− and POX4X3−, so its pH is the mean of the two flanking constants: (7.21+12.35)/2=9.78.