Dilute AgNO3 is added slowly to a solution that is 0.1 M in each of Cl-, Br- and I-. Given K_sp: AgCl = 1.8x10^-10, AgBr = 5.0x10^-13, AgI = 8.5x10^-17. The first precipitate to appear is

NEET levelSingle correct optionDifficulty 1 of 3ia171

Dilute $AgNO X_{3}$ is added slowly to a solution that is $0.1 M$ in each of $Cl X^{-}$ , $Br X^{-}$ and $I X^{-}$ . Given $K_{s p}$ : $AgCl = 1.8 \times 1 0^{- 10}$ , $AgBr = 5.0 \times 1 0^{- 13}$ , $AgI = 8.5 \times 1 0^{- 17}$ . The first precipitate to appear is

For equal anion concentrations the salt with the smallest

K_{s p}

needs the smallest

[Ag X^{+}]

8.5 \times 1 0^{- 16} M

for

AgI

versus

5 \times 1 0^{- 12}

for

AgBr

and

1.8 \times 1 0^{- 9}

for

AgCl

. So

AgI

precipitates first.