$20 mL$ of $0.10 M$ HCl is titrated with $0.10 M$ NaOH. After $10 mL$ of NaOH have been added the pH of the mixture is

Answer: C

Moles of

H X^{+}

left

= 2.0 - 1.0 = 1.0 mmol

30 mL

, so

[H X^{+}] = 0.0333 M

and

pH = 1.48

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