JEE Main levelOne or more correct optionsDifficulty 2 of 3ia084
A sparingly soluble salt MA has Ksp=1.0×10−10 and HA has Ka=1.0×10−5. In a buffer of fixed pH the solubility is S=Ksp(1+[HX+]/Ka) (neglect hydrolysis of MX+). Select the correct statement(s).
AAt pH 7 the solubility is 1.0×10−5M
BAt pH 5 the solubility is 1.4×10−5M
CAt pH 3 the solubility is 3.2×10−4M
DThe solubility at pH 2 is more than ten times that at pH 7
Answer: A, B, D
Using the formula: pH 7 gives 1.00×10−5M; pH 5 gives 1.41×10−5M; pH 3 gives 1.00×10−4M (not 3.2×10−4M); pH 2 gives 3.16×10−4M, i.e. 31.5 times the pH 7 value.