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Ionic Equilibrium II
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Acid-base titration curves and indicators
JEE Main level
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Difficulty 2 of 3
ia041
25.0 mL of 0.100 M acetic acid (
K
a
=
1.8
×
1
0
−
5
) is titrated with 0.100 M NaOH. The pH after adding 10.0 mL of NaOH is
A
4.92
B
4.57
C
4.74
D
2.87
Answer: B
Initial acid
=
2.5
mmol; NaOH added
=
1.0
mmol, giving 1.0 mmol acetate and 1.5 mmol acetic acid. pH
=
p
K
a
+
lo
g
(
1.0/1.5
)
=
4.745
−
0.176
=
4.57
. The choice 4.92 inverts the ratio.
Practice Ionic Equilibrium II
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