Answer: A, B, C
Kh1=Kw/Ka2=2.13e−04, [OHX−]=4.61e−03 M, pH =11.66. The first step gives equal [HCOX3X−] and [OHX−]. In the second step Kh2=[HX2COX3][OHX−]/[HCOX3X−]=Kw/Ka1=2.33e−08, and since [HCOX3X−]≈[OHX−], [HX2COX3]≈2.3e−08 M, negligible. D is wrong. Answer A, B, C.