A 2.0 L vessel contains 0.10 mol N2 and 0.30 mol H2 at 300 K. Taking R = 0.0821 L atm K^-1 mol^-1, which statements are correct?

The total pressure is about 4.93 atm

The partial pressure of H2 is three times that of N2

If the N2 were removed, the pressure would fall by 25%

The total pressure is about 4.93 atm

The partial pressure of H2 is three times that of N2

If the N2 were removed, the pressure would fall by 25%

The mass fraction of H2 in the mixture is 0.75

JEE Advanced levelOne or more correct optionsDifficulty 3 of 3ig104

A $2.0 L$ vessel contains $0.10 mol$ $N X_{2}$ and $0.30 mol$ $H X_{2}$ at $300 K$ . Taking $R = 0.0821 L atm K^{- 1} mo l^{- 1}$ , which statements are correct?

P = \frac{0.40 \times 0.0821 \times 300}{2.0} = 4.926 atm

(A). Partial pressures are in the mole ratio

3 : 1

(B).

N X_{2}

25%

of the moles, so removing it drops

P

25%

(C). Masses:

N X_{2}

2.8 g

H X_{2}

0.6 g

; mass fraction of

H X_{2}

= 0.6/3.4 = 0.18

, not

0.75

(D wrong).