10 mL of a gaseous hydrocarbon on complete combustion gives 30 mL of CO2 and 40 mL of water vapour, all measured at the same temperature and pressure above 100 degC. The hydrocarbon is

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$10 mL$ of a gaseous hydrocarbon on complete combustion gives $30 mL$ of $CO X_{2}$ and $40 mL$ of water vapour, all measured at the same temperature and pressure above $10 0^{\circ} C$ . The hydrocarbon is

Volume ratios equal mole ratios.

CO X_{2} : hydrocarbon = 3

, so

x = 3

H X_{2} O : hydrocarbon = 4 = y /2

, so

y = 8

. The hydrocarbon is

C X_{3} H X_{8}