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NEET levelSingle correct optionDifficulty 1 of 3hc169

In the free radical chlorination of methane, which of the following is a chain propagation step?

A $Cl X_{2} 2 Cl \cdot$ (homolysis by light)
B $Cl \cdot + CH X_{4} \cdot CH X_{3} + HCl$
C $\cdot CH X_{3} + Cl \cdot CH X_{3} Cl$
D $2 \cdot CH X_{3} C X_{2} H X_{6}$

Answer: B

A propagation step consumes one radical and produces another.

Cl \cdot

abstracting H from methane gives

\cdot CH X_{3}

, so it propagates the chain. The first is initiation, and the last two are termination steps.

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