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JEE Advanced levelSingle correct optionDifficulty 3 of 3hc128

Sodium ethynide, , is treated with 2-bromo-2-methylpropane. The main outcome is

  1. A3,3-dimethylbut-1-yne, by substitution
  2. B3,3-dimethylbut-1-yne, as the major product by substitution
  3. C2-methylpropan-2-ol
  4. D2-methylpropene and ethyne, by elimination

Answer: D

The acetylide ion is a strong base as well as a nucleophile. A tertiary halide cannot undergo and in this strongly basic medium E2 dominates: the acetylide removes a beta hydrogen, giving 2-methylpropene and ethyne. Acetylide alkylation works well only with methyl and primary halides.
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