Answer: C
Steps (i)-(ii) give hex-3-yne; Lindlar reduction gives (Z)-hex-3-ene by syn addition. Bromine adds anti through a bromonium ion. Anti addition to a cis-alkene gives the (R,R)/(S,S) pair in equal amounts (racemate); trans-alkenes would give the meso compound. The attack on a symmetric bromonium ion is equally likely at either face, so the racemate is formed.