Answer: B
The propynide ion adds to the carbonyl carbon of ethanal, and protonation gives CHX3−CH(OH)−C≡C−CHX3, pent-3-yn-2-ol (P). Lindlar reduction is a syn addition of HX2 that stops at the alkene, giving the cis alkene CHX3−CH(OH)−CH=CH−CHX3, (Z)-pent-3-en-2-ol.