Numerical answer type, answer in L, tolerance 0.05.
Answer: 2.1 L
Pure CaCX2 = 10.0×0.80=8.0 g, and its molar mass is 64 g/mol, so it is 0.125 mol. One mole of carbide gives one mole of ethyne, so the theoretical amount is 0.125 mol. The collected amount is 0.125×0.75=0.09375 mol, and the volume is 0.09375×22.4=2.10 L.