Answer: A, C
2,3-Dimethylbutane is (CHX3)X2CH−CH(CHX3)X2. Adding HX2 across the C=C of CHX2=C(CHX3)−CH(CHX3)X2 or (CHX3)X2C=C(CHX3)X2 gives it. 3,3-Dimethylbut-1-ene gives 2,2-dimethylbutane and 2-methylpent-1-ene gives 2-methylpentane, since hydrogenation does not change the carbon skeleton.