Answer: B
Protonation gives the secondary cation (CHX3)X2CH−CHX+−CHX3. A 1,2-hydride shift converts it into the more stable tertiary cation (CHX3)X2CX+−CHX2CHX3, which is captured by bromide. The major product is 2-bromo-2-methylbutane, not the unrearranged 2-bromo-3-methylbutane.