Answer: A, B
SN2 on (S)-2-bromooctane is a one-step concerted backside displacement: the rate is first order in bromide and first order in azide, and the stereocentre is inverted, giving the (R)-azide (the priority order azide, hexyl, methyl, H matches Br, hexyl, methyl, H, so the label flips). There is no carbocation, so no racemisation, and there is no separate ionisation step.