Answer: A
A positive iodoform test indicates CHX3COX− or CHX3CH(OH)X−. Butan-2-one, CHX3COCHX2CHX3, loses the CHX3 as CHIX3 and the remaining CHX3CHX2COOX−NaX+ (sodium propanoate) has 3 carbons. Butanal, 2-methylpropanal and cyclobutanol do not have the required group.