Answer: B, C
Protonation of CHX2=CH−CH(CHX3)X2 gives the secondary cation CHX3−CHX+−CH(CHX3)X2. A 1,2-hydride shift from the neighbouring CH gives the tertiary cation CHX3CHX2−CX+(CHX3)X2, which gives 2-bromo-2-methylbutane (major). Direct capture gives the minor 2-bromo-3-methylbutane. A primary cation is not formed under ionic conditions, and a methyl shift from that carbon would not give a tertiary cation.