NEET levelSingle correct optionDifficulty 1 of 3hx077
CHX3MgBr is treated with solid COX2 and then with dilute acid. The product is
Apropanoic acid
Bmethanol
Cethanal
Dethanoic acid
Answer: D
The methyl carbanion adds to the carbon of COX2 to give CHX3COOMgBr. Acidification liberates CHX3COOH, which has one carbon more than the Grignard alkyl group.