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NEET levelSingle correct optionDifficulty 1 of 3hx038

(R)-2-Bromobutane reacts with aqueous $NaOH$ by a pure $S_{N} 2$ mechanism. The product butan-2-ol is

A(R)-butan-2-ol
B(S)-butan-2-ol
Cracemic butan-2-ol
Dmeso-butan-2-ol

Answer: B

S_{N} 2

proceeds with Walden inversion. In the halide the priorities are

Br > C X_{2} H X_{5} > CH X_{3} > H

and in the alcohol

OH > C X_{2} H X_{5} > CH X_{3} > H

, the same order, so inversion changes the label from R to S.

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