Answer: D
Protonation of the double bond occurs at the carbon that gives the more stable carbocation. Adding HX+ to the CH−CHX3 carbon gives the benzylic cation CX6HX5−CHX+−CHX2CHX3, stabilised by resonance with the ring. Bromide then gives CX6HX5−CHBr−CHX2CHX3, (1-bromopropyl)benzene.