Numerical answer type, tolerance 0.5.
Answer: 3
The cation shown is the 3-methylbutyl cation. A 1,2-hydride shift from C2 gives the secondary 3-methylbutan-2-yl cation. A second 1,2-hydride shift from C3 gives the tertiary 2-methylbutan-2-yl cation; a methyl shift from the secondary cation just regenerates the same secondary cation. The set is the primary, the secondary and the tertiary cation, so the total is 3.