Conformers A and B interconvert much faster than either reacts, and each gives a different product irreversibly (A gives PA, B gives PB). B is $8.0\mathrm{kJ}\mathrm{mo}{\mathrm{l}}^{-1}$ higher in free energy than A. The transition state leading to PA lies $62.0\mathrm{kJ}\mathrm{mo}{\mathrm{l}}^{-1}$ above A and that leading to PB lies $58.0\mathrm{kJ}\mathrm{mo}{\mathrm{l}}^{-1}$ above A. At 298 K ($R=8.314\mathrm{J}\mathrm{mo}{\mathrm{l}}^{-1}{\mathrm{K}}^{-1}$) the product ratio is about

1. APA : PB $\approx$ 5 : 1
2. BPB : PA $\approx$ 5 : 1
3. CPA : PB $\approx$ 25 : 1
4. DPB : PA $\approx$ 127 : 1