NEET levelSingle correct optionDifficulty 1 of 3g3121
Free radical monobromination of propane gives mainly
Aan equimolar mixture of 1- and 2-bromopropane
B2-bromopropane
C1-bromopropane
D1,3-dibromopropane
Answer: B
Bromine radicals are highly selective and prefer to abstract the secondary hydrogen, which gives the more stable secondary radical through a late transition state. So 2-bromopropane is the major product.